FISEKON GmbH – Fischer Elektrokonstruktion

06 — Calculators

Current-carrying capacity as installed

The tabulated value applies to a single cable at 30 °C. In the plant it sits in a filled duct beside eleven others, with a machine standing over it. The correction factors are the part people skip in a quick estimate — and the part that overturns the design.

Input

From the table in your standard for cross-section, installation method and insulation, at 30 °C ambient.

From the table in your standard. At 30 °C it is 1, above that smaller, below that larger.

From the table in your standard, depending on the number and arrangement of loaded circuits.

Buried installation, soil thermal resistivity, thermal insulation. With none of these, leave at 1.

Miniature circuit breakers are typically 1.45, gG fuses typically 1.6. The device data sheet governs.

Result

Current-carrying capacity as installed
A
Combined factor
Utilisation by the design current
%
Assessment of the coordination

A guide, not a design to standard. We give no warranty for the correctness of the results, the applicable standards and case-by-case verification govern.

Worked example

The default case the calculator starts with, worked through once. Change the values above and it recalculates immediately.

Inputs

Base current-carrying capacity
41 A
Ambient temperature factor
0.87
Grouping factor
0.7
Further factors
1
Design current I_B
20 A
Rated current of the protective device I_n
25 A
Conventional tripping current factor I₂ / I_n
1.45

Result

Current-carrying capacity as installed
25 A
Combined factor
0.609
Utilisation by the design current
80.1 %
Assessment of the coordination
The protective device is too large for the cable: I_n exceeds the capacity.

Formula

  • I_z = I_z0 · f_temperature · f_grouping · f_other
  • First condition: I_B ≤ I_n ≤ I_z
  • Second condition: I₂ ≤ 1.45 · I_z
  • with I₂ = k₂ · I_n

Assumptions and standards

  • The base value and the correction factors come from the standard you apply and are entered here, not looked up. We deliberately do not reproduce normative tables: a wrong tabulated value inside a calculator is more dangerous than no calculator at all.
  • The two conditions are the usual coordination of cable and overload protection.
  • Short-circuit protection, the disconnection condition and voltage drop are separate proofs and not covered here.

Frequently asked

Where do I get the base value?

From the current-carrying capacity table for your case: conductor material, insulation, number of loaded cores and installation method determine it. The same cable carries considerably more in free air than in a wall under thermal insulation.

What does the second condition mean?

It ensures the protective device still disconnects in time under a small, sustained overload. The conventional tripping current is the current at which the device reliably operates. For miniature circuit breakers it is typically 1.45 times the rated current, in which case the condition is met automatically once the first is. For fuses at 1.6 times it is the stricter one.

May I simply multiply several factors?

For temperature and grouping that is the usual approach. For buried installation further influences arise that cannot always be expressed cleanly as a separate factor. Check the notes to your table in that case.

Calculating is the easy part.

A formula gives you a number. Designing a plant also demands installation method, grouping, discrimination, the standards in force and a look at the installed base. That is what we take on.

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33428 Marienfeld (Harsewinkel)
Gütersloh officeWagenfeldstr. 2
33332 Gütersloh

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