FISEKON GmbH – Fischer Elektrokonstruktion

10 — Calculators

Short-circuit current at the transformer

The short-circuit current determines the breaking capacity the downstream protective devices need. For a first estimate, three figures from the transformer nameplate are enough.

Input

As stated on the nameplate.

Result

Initial symmetrical short-circuit current I″kRMS value at the low-voltage terminals
kA
Rated current
A
Ratio I″k / Iᵣ

A guide, not a design to standard. We give no warranty for the correctness of the results, the applicable standards and case-by-case verification govern.

Worked example

The default case the calculator starts with, worked through once. Change the values above and it recalculates immediately.

Inputs

Rated apparent power
630 kVA
Nominal voltage, low-voltage side
400 V
Short-circuit voltage uₖ
6 %

Result

Initial symmetrical short-circuit current I″k
15.2 kA
Rated current
909 A
Ratio I″k / Iᵣ
16.7

Formula

  • Iᵣ = Sᵣ / (√3 · Uᵣ)
  • I″k = Iᵣ / (uₖ / 100)

Assumptions and standards

  • The calculation assumes an infinitely strong upstream source, neglecting its impedance, the real network limits the current further, so the result is on the safe side.
  • Only the transformer is considered, not cables, busbars or motor contribution.
  • The result is the RMS value I″k, which governs the rated breaking capacity of protective devices. The peak short-circuit current iₚ, the crest of the first half-cycle, governing the dynamic strength of busbars, follows from iₚ = κ · √2 · I″k with κ ≈ 1.8 and is therefore about 2.5 times as high.
  • A binding design requires calculation to IEC 60909.

Frequently asked

Why is the value higher than in the network study?

Because the upstream network impedance is neglected here. In practice it reduces the short-circuit current, often by 5 to 15 %. For selecting breaking capacity, erring high is the right direction.

What does uk on the nameplate mean?

The voltage that has to be applied on the high-voltage side so that rated current flows on the low-voltage side under short circuit, given as a percentage of nominal voltage. A small uk means a high short-circuit current.

Calculating is the easy part.

A formula gives you a number. Designing a plant also demands installation method, grouping, discrimination, the standards in force and a look at the installed base. That is what we take on.

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